x^2-5500x+2500000=0

Solution for x^2-5500x+2500000=0 equation:

x^2-5500x+2500000=0

a = 1; b = -5500; c = +2500000;
Δ = b2-4ac
Δ = -55002-4·1·2500000
Δ = 20250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20250000}=4500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5500)-4500}{2*1}=\frac{1000}{2}
=500
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5500)+4500}{2*1}=\frac{10000}{2}
=5000
$